Vectors#

Many problems in chemistry and physics involve working with vector quantities. A common definition of a vector in a physics context is a quantity with both magnitude and direction; for example, the positions or velocities of atoms, or the forces acting on atoms within a molecule.

Example 1: Atomic positions.#

Defining atomic positions requires three pieces of information: the location of some reference point in space, called the origin, the distance of each atom from the origin, and the direction we move from the origin to reach the atom. Positions are therefore vector quantities, since they define both magnitude and distance (relative to the origin).

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Fig. 1 Defining atomic positions requires knowing both distance and direction with respect to some reference origin.#

A common choice for describing atomic positions is to use Cartesian coordinates, i.e. \((x, y)\) in two dimensions, or \((x, y, z)\) in three dimensions [1]; this will be familiar from the earlier exercises on calculating interatomic distances.

In two dimensions, any position can be described by giving both the \(x\) and \(y\) coordinate.

../_images/position_vectors_2.svg

Fig. 2 Describing positions using Cartesian coordinates, i.e. \((x, y)\) coordinates in two dimensions, or \((x, y, z)\) in three dimensions.#

Using the language of vectors, this choice of \(x\) and \(y\) coordinates defines a pair of basis vectors, which we will denote \(\mathbf{i}\) and \(\mathbf{j}\). [2]

../_images/position_vectors_3.svg

Fig. 3 In two dimensions we have two implicit basis vectors \(\mathbf{i}\) and \(\mathbf{j}\). Any position can be expressed as a linear combination of these basis vectors.#

Any position vector \(r = (x, y)\) can be expressed as a linear combination of these basis vectors, i.e. \(r = x \times \mathbf{i} + y \times \mathbf{j}\). This means one way to think about the usual notation \((x, y)\) is that the two numbers describe the coefficients of \(\mathbf{i}\) and \(\mathbf{j}\) for a given linear combination.

../_images/position_vectors_4.svg

Fig. 4 The \((x, y)\) coordinates given above are the coefficients used to define each position in the basis \((\mathbf{i}, \mathbf{j})\).#

This might seem an overly complicated way of thinking about coordinates in Cartesian space, but it highlights that writing down a position vector such as \((3, 4)\) is only meaningful if the basis vectors are defined. If we had chosen a different set of basis vectors, the same positions would be described with different vectors.

../_images/position_vectors_alternate_basis.svg

Fig. 5 The same three positions described using a different basis.#

Vector addition, subtraction, scaling, and “multiplication”#

Vectors can be added together by adding the coefficients of each basis vector.

../_images/vector_addition.svg

Fig. 6 Vector addition.#

For example, adding together the vectors \(\mathbf{v}_1=(5,1)\) and \(\mathbf{v}_2=(2,4)\) gives us a new vector \(\mathbf{v}_3=(7,6)\), which can be understood by writing \(\mathbf{v}_1\) as \((5\mathbf{i}+1\mathbf{j})\) and \(\mathbf{v}_2\) as \((2\mathbf{i}+4\mathbf{j})\). Adding \(\mathbf{v1}\) and \(\mathbf{v2}\) then gives \(\left[(5\mathbf{i}+1\mathbf{j})+(2\mathbf{i}+4\mathbf{j})\right]\) and common terms can be collected together to give \(\left[(5+2)\mathbf{i}+(1+4)\mathbf{j}\right]=(7\mathbf{i}+6\mathbf{j})\).

Subtracting one vector from another follows the same rules, but with the coefficients of each basis vector subtracted; e.g. \(\mathbf{v}_1-\mathbf{v}_2=(3,-3)\).

Scaling a vector involves multiplying by a scalar (hence the name). This changes the length of the vector, but not the direction, and involves multiplying each of the basis vector coefficients by the scalar value. i.e. \(\mathbf{v}_\mathrm{1}=(2,3)\). \(\mathbf{v}_1\times2=(4,6)\). Again, we can understand this by expanding out the original vector in terms of the basis vectors, \(\mathbf{i}\) and \(\mathbf{j}\): \((2\mathbf{i}+3\mathbf{j})\times2=(4\mathbf{i}+6\mathbf{j})\).

The dot-product and the cross-product#

We can also “multiply” two vectors together, although this is more complex. In fact there are two standard ways to deinfe “multiplication:; of vectors.

The dot product is also known as the “scalar product”. This operation takes two vectors and returns a scalar quantity. The dot product of two vectors is denoted \(\mathbf{a}\cdot\mathbf{b}\), and is defined as

\[ \mathbf{a}\cdot\mathbf{b} = \sum_ia_ib_i = a_1b_1 + a_2b_2 + \ldots + a_nb_n.\]

For example, if \(\mathbf{a}=(2,1)\) and \(\mathbf{b}=(3,2)\) then \(\mathbf{a}\cdot\mathbf{b}\) is given by

\[\begin{split} \begin{aligned} \mathbf{a}\cdot\mathbf{b} & = & (x_\mathrm{a} \times x_\mathrm{b})+ (y_\mathrm{a}\times y_\mathrm{b})\\ & = & (2\times3 + 1\times2) \\ & = & 8 \end{aligned} \end{split}\]

An equivalent definition of the dot product is

\[\mathbf{a}\cdot\mathbf{b} = \left\lVert\mathbf{a}\right\rVert \left\lVert\mathbf{b}\right\rVert \cos\theta,\]

where \(\left\lVert\mathbf{a}\right\rVert\) is the length of vector \(\mathbf{a}\), and \(\theta\) is the angle between \(\mathbf{a}\) and \(\mathbf{b}\).

The cross-product is also known as the “vector product”. This operation takes two vectors and returns a vector quantity, with both magnitude and direction. The cross product between vectors \(\mathbf{a}\) and \(\mathbf{b}\) is denoted \(\mathbf{a}\times\mathbf{b}\) and is defined as a vector perpendicular to the plane containing \(\mathbf{a}\) and \(\mathbf{b}\) with a length given by the area of the parallelogram with \(\mathbf{a}\) and \(\mathbf{b}\) as sides.

This can be computed as

\[\mathbf{a}\times\mathbf{b} = \left\lVert\mathbf{a}\right\rVert \left\lVert\mathbf{b}\right\rVert \sin\theta\,\mathbf{n},\]

where \(\mathbf{n}\) is the unit vector (a vector with length 1) perpendicular to the plane containing \(\mathbf{a}\) and \(\mathbf{b}\).